Stand in line question

JavaScript
#1

here is what it gives.

function nextInLine(arr, item) {
  // Your code here
  
  return item;  // Change this line
}

// Test Setup
var testArr = [1,2,3,4,5];

// Display Code
console.log("Before: " + JSON.stringify(testArr));
console.log(nextInLine(testArr, 6)); // Modify this line to test
console.log("After: " + JSON.stringify(testArr));

I did figure out the answer i’m just wondering why if I use

function nextInLine(arr, item) {
  // Your code here
  
  var remo=arr.shift();
  arr=arr.push(item);
[spoiler] 
 //arr.push(item);
  //return arr.shift();
[spoiler]  
return remo;  // Change this line
}

// Test Setup
var testArr = [1,2,3,4,5];

// Display Code
console.log("Before: " + JSON.stringify(testArr));
console.log(nextInLine(testArr, 6)); // Modify this line to test
console.log("After: " + JSON.stringify(testArr));

it doesn’t pass and if i put the shift after the push i get TypeError: arr.shift is not a function the only difference to me is i’m trying to store the value before returning it.

#2

I cleaned up your code.
You need to use triple backticks to post code to the forum.
See this post for details.

#3