Hi everyone. On the challenge, Iterate Through an Array with a For Loop, there is a paragraph that says, **“Remember that Arrays have zero-based numbering, which means the last index of the array is length - 1. Our condition for this loop is i < arr.length, which stops when i is at length - 1.”** I don’t understand it. Could someone explain it to me? Thanks.

What part don’t you understand?

Arrays are indexed starting at 0.

`var exampleArray = [ 'a', 'b', c'];`

In this example `'a'`

is the value at index `0`

. The length of this example array is `3`

. The index of the last item is `2`

.

`<`

means “less than” so a loop with `i < arr.length`

will only continue while `i`

is **less than** the length of `arr`

.

@IAScoding1

Yes, tricky at first but you get used to it. Length is not zero based, but arrays are zero based.

Using the above example:

`var exampleArray = [ 'a', 'b', c'];`

exampleArray[0] is 'a’

exexampleArray[1] is 'b’

exampleArray[2] is 'c’

exampleArray[3] is ‘d’

but with the four elements:

exampleArray.length is 4

You can see if you use the length as an index there is a problem, there is no exampleArray[4], hence you will always be using .length - 1 to define the last element in the array.

Does that make sense? This is is the convention and avoids the confusion of length zero holding one element.

-WWC

The part I don’t understand is that the last index of the array is length - 1. Wouldn’t the last index of the array be length 5?

`.length()`

gives us the number of elements in an array.

```
var arr1 = ['a', 'b', 'c']; // length is 3
var arr2 = ['lions', 'tigers', 'bears', 'OH MY!']; // length is 4
```

The last element of any array will have an index of one less than the length.

`arr1[arr1.length -1]`

is equivalent to `arr1[3 - 1]`

is equivalent to `arr1[2]`

which is `'c'`

.

Thank you. This helps.