# Unexpected return during algorithm challenge

Hello all I am working on this challenge:

https://learn.freecodecamp.org/javascript-algorithms-and-data-structures/basic-algorithm-scripting/return-largest-numbers-in-arrays

and I have been able to get the code to return an array, but it is filled with the two highest numbers of each sub-array rather than just the single highest number. my code follows:

``````function largestOfFour(arr) {

let sorted = [];
for (let i = 0; i < arr.length; i++) {
let arrInner = arr[i];
for (let  j = 0; j < arrInner.length; j++) {
sorted.push(arrInner.sort().pop());
}
} return sorted;
}

console.log(largestOfFour([[4, 5, 1, 3], [13, 27, 18, 26], [32, 35, 37, 39], [1000, 1001, 857, 1]]));
``````

so I am getting [5,4,27,26,39,37,857,1001] rather than [5, 27, 39, 1001].

Any help is greatly appreciated!

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How are you testing to make sure that the number you are adding to the array is the largest?

1. If it were not for the fact that you changed the length of the innerArray (by pop) you would just get the full array back in sorted order.

Removing the inner loop:

``````function largestOfFour(arr) {

let sorted = [];
for (let i = 0; i < arr.length; i++) {
let arrInner = arr[i];
sorted.push(arrInner.sort().pop());
}
return sorted;
}

Returns: [5, 27, 39, 857]
``````
1. Sorting the last array is not giving you what you want.
``````[1000, 1001, 857, 1].sort().pop()
Returns: 857
``````

Hey I figured it out, thanks for cluing me in on that unnecessary inner loop! That really got the ball rolling. I ended up running a function inside of sort() as follows:

`````` sorted.push(arrInner.sort(function( a, b) {return a - b}).pop());
``````

This “sorted” (pun totally intended) the rest of the code out and now it is working. Thanks all for your input!