Use Destructuring Assignment to Pass an Object as a Function's Parameters - why I am not calling the object?

JavaScript
1

Tell us what’s happening:
I don’t get why in this case I don’t need to call stats inside the function. Is it because it is the only object that there is?

I use return function half({max, min}) {}, but does it works because there is only an object that has max and min properties and so as good practive I should call stats when using Destructuring Assignment like in the examples, or it just works like that?

Your code so far


const stats = {
  max: 56.78,
  standard_deviation: 4.34,
  median: 34.54,
  mode: 23.87,
  min: -0.75,
  average: 35.85
};
const half = (function() {
  "use strict"; // do not change this line

  // change code below this line
  return function half({max, min}) {
    // use function argument destructuring
    return (max + min) / 2.0;
  }  // change code above this line

})();
console.log(stats); // should be object
console.log(half(stats)); // should be 28.015

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 6.1; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/69.0.3497.100 Safari/537.36.

Link to the challenge:
https://learn.freecodecamp.org/javascript-algorithms-and-data-structures/es6/use-destructuring-assignment-to-pass-an-object-as-a-functions-parameters/

1 Like
2

It worked because stats has max and min properties

3

And if there is more than one object with those properties?

4

you passed stats as an argument to the function… what gets passed to the function is the result you get

5

I have the same question. I don’t see where stats is passed as an argument to the function … only that max and min are passed. But since they are properties of the object “stats”, how does the function know to look in that object?

6

I found out! last line, console.log(half(stats));

7

Oh right! So cool! Thanks!