Use Higher-Order Functions map, filter, or reduce to Solve a Complex Problem

JavaScript
22

hmm, what’s a way to check for a remainder?

23

Could you use the % ? Maybe say num % 2 === 0

24

Close, but num % 2 checks if a number is evenly divisible by 2.

25

Ahhhhhhh so I should use 1

const squareList = arr => {
  // Only change code below this line
  let positiveIntegersSquared = arr.filter(num => {
    if (num > 0 && num % 1 === 0) return num; 
  }).map(num => { return num * num });
  return positiveIntegersSquared;
  // Only change code above this line
};

const squaredIntegers = squareList([-3, 4.8, 5, 3, -3.2]);
console.log(squaredIntegers);
26

Thank you so much for your patience Jeremy! Love the way you help me out without giving me the answer or obvious hints

1 Like
27

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