What is difference between arr=[...arguments] and [arr0,arr1]=arguments

JavaScript
#1

Tell us what’s happening:
Describe your issue in detail here.
i don’t know where is my issue?

and this’s the solution to this challenge.
Your code so far

function addTogether() {
  const arr=[...arguments];
  
  if(typeof(arr[0])!=="number")
      return undefined;
  if(arr[1]===undefined)
  
    return (arr[1])=>addTogether(arr[0],arr[1]);
  
  if(typeof(arr[1])!=="number")
    return undefined;
  return arr[0]+arr[1];


}

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/100.0.4896.75 Safari/537.36 Edg/100.0.1185.36

Challenge: Arguments Optional

Link to the challenge:

#2

What is difference between…

  arr=[...arguments]

That is making a shallow copy of arguments and storing it in arr.

[arr0,arr1]=arguments

That is destructuring the array arguments. It will make a copy of the first element (the reference if it is a reference type) in that array and store it in arr0 and store the second in arr1.

#3

What does this mean?

return (arr[1])=>addTogether(arr[0],arr[1]);
#4

function addTogether() {
const [first, second] = arguments;
if (typeof(first) !== “number”)
return undefined;
if (second === undefined)
return (second) => addTogether(first, second);
if (typeof(second) !== “number”)
return undefined;
return first + second;
}
and this is the solution to the problem.
I imitated that.

#5

i see.that’s very helpful,thank you.

#6

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