Why the below is incorrect (about every() and Array.isArray)

JavaScript
1

Just solved steamroller,
however,
not fully understand the below situation:

arr = [1, {}, [3, [[4]]]]

console.log(arr.every(Array.isArray));//false

console.log(arr.every(!(Array.isArray)));//TypeError: false is not a function
2

.every takes a function as an argument. Putting the ! out from coerces the function pointer into a boolean.

1 Like
3

In my solution I used this:

arr.every(elem => (!Array.isArray(elem)))

I was trying to write it with less code, but this:

arr.every((!Array.isArray))

is also incorrect apparently.

4

It’s incorrect for the same reason. You need a function as the callback.

5

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