Basic JavaScript - Counting Cards

Tell us what’s happening:
I want to know the difference and how them work about if and switch

Your code so far

//let count = 0;
//function cc(card) {
 // if (card=2||3||4||5||6){
//    count++;
//  }
 // else if (card=10||'J'||'Q'||'K'||'A'){
//    count--;
 // }
//   if(count > 0) {
 //   return count + " Bet";
//  } else {
 //   return count + " Hold";
//  }
let count = 0;
function cc(card) {
  switch(card) {
    case 2:
    case 3:
    case 4:
    case 5:
    case 6:
      count++;
      break;
    case 10:
    case 'J':
    case 'Q':
    case 'K':
    case 'A':
      count--;
  }
  if(count > 0) {
    return count + " Bet";
  } else {
    return count + " Hold";
  }
  }




  

  // Only change code above this line


cc(2); cc(3); cc(7); cc('K'); cc('A');

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User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/114.0.0.0 Safari/537.36

Challenge: Basic JavaScript - Counting Cards

Link to the challenge:

can you write the if statement that has the same output like switch statement

It still doesnt work
let count = 0;
function cc(card) {
if (card=2){
count++;
}
else if (card=3){
count++;
}
else if (card=4){
count++;
}
else if (card=5){
count++;
}
else if (card=6){
count++;
}
else if (card=10){
count–;
}
else if (card=‘J’){
count–;
}
else if (card=‘Q’){
count–;
}
else if (card=‘K’){
count–;
}
else if (card=‘A’){
count–;
}
if(count > 0) {
return count + " Bet";
} else {
return count + " Hold";
}

}

I got it with this
let count = 0;
function cc(card) {
// Only change code below this line

if (card > 1 && card < 7) {
count++;
}
else if (card == 10 || card==“J”|| card==“Q”|| card==“K”||card== “A”) {
count–;
}
var holdbet= “Hold”;
if (count>0){
holdbet=“Bet”;
return count + " " + holdbet
}
else{
return count + " " + holdbet}

// Only change code above this line
}

cc(2); cc(3); cc(7); cc(‘K’); cc(‘A’);

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