Basic JavaScript - Counting Cards

Tell us what’s happening:
I want to know the difference and how them work about if and switch

``````//let count = 0;
//function cc(card) {
// if (card=2||3||4||5||6){
//    count++;
//  }
// else if (card=10||'J'||'Q'||'K'||'A'){
//    count--;
// }
//   if(count > 0) {
//   return count + " Bet";
//  } else {
//   return count + " Hold";
//  }
let count = 0;
function cc(card) {
switch(card) {
case 2:
case 3:
case 4:
case 5:
case 6:
count++;
break;
case 10:
case 'J':
case 'Q':
case 'K':
case 'A':
count--;
}
if(count > 0) {
return count + " Bet";
} else {
return count + " Hold";
}
}

// Only change code above this line

cc(2); cc(3); cc(7); cc('K'); cc('A');
``````

User Agent is: `Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/114.0.0.0 Safari/537.36`

Challenge: Basic JavaScript - Counting Cards

can you write the if statement that has the same output like switch statement

It still doesnt work
let count = 0;
function cc(card) {
if (card=2){
count++;
}
else if (card=3){
count++;
}
else if (card=4){
count++;
}
else if (card=5){
count++;
}
else if (card=6){
count++;
}
else if (card=10){
count–;
}
else if (card=‘J’){
count–;
}
else if (card=‘Q’){
count–;
}
else if (card=‘K’){
count–;
}
else if (card=‘A’){
count–;
}
if(count > 0) {
return count + " Bet";
} else {
return count + " Hold";
}

}

I got it with this
let count = 0;
function cc(card) {
// Only change code below this line

if (card > 1 && card < 7) {
count++;
}
else if (card == 10 || card==“J”|| card==“Q”|| card==“K”||card== “A”) {
count–;
}
var holdbet= “Hold”;
if (count>0){
holdbet=“Bet”;
return count + " " + holdbet
}
else{
return count + " " + holdbet}

// Only change code above this line
}

cc(2); cc(3); cc(7); cc(‘K’); cc(‘A’);

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