Basic JavaScript - Passing Values to Functions with Arguments

JavaScript
1

Tell us what’s happening:
Describe your issue in detail here. my code seems not to be working . How should I modify it?

Your code so far

function functionWithArgs(a, b) {
  console.log(a + b);
}

functionWithArgs(1, 2);

function functionWithArgs(a, b) {
  console.log(a + b);
}

functionWithArgs(7, 9);

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/114.0.0.0 Safari/537.36

Challenge: Basic JavaScript - Passing Values to Functions with Arguments

Link to the challenge:

2

Aren’t you declaring a function twice?

3

So the directions say

  1. Create a function called functionWithArgs that accepts two arguments and outputs their sum to the dev console.
  2. Call the function with two numbers as arguments.
function functionWithArgs(a, b) {
  console.log(a + b);
}

functionWithArgs(1, 2);


function functionWithArgs(a, b) {
  console.log(a + b);
}

Directions only ask for one function not two. As a note, you dont want to use two functions with the same name as a general rule. What will happen is the function that comes last will override the first function.

4

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