Tell us what’s happening:
Describe your issue in detail here.
Your code so far
function functionWithArgs () {console.log(1+2, 7+9);
}
functionWithArgs()
functionWithArgs()
```were i made mistake
Tell us what’s happening:
Describe your issue in detail here.
Your code so far
function functionWithArgs () {console.log(1+2, 7+9);
}
functionWithArgs()
functionWithArgs()
```were i made mistake
What are you trying to do here? Your function doesn’t accept arguments and you called the same function twice.
The function should have two arguments:
function nameOfTheFunction(arg1, arg2) {
here you should make a statement that prints the sum of `arg1 + arg2` in the console - (the console.log() method outputs a message to the web console)
}
Then, you should call that function with two numbers as arguments:
for example: nameOfTheFunction(2, 4);
The console will show the number 6.