Basic JavaScript - Passing Values to Functions with Arguments

JavaScript
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Tell us what’s happening:

Hello everyone kindly guide me out with this challenge.

Your code so far

function functionWithArgs(1,2) {
  console.log(1+2);
  
}

Your browser information:

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Challenge Information:

Basic JavaScript - Passing Values to Functions with Arguments

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Please don’t forget to talk to us about how the instructions or error message is confusing. Communication is a critical coding skill

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how do I create a function that accepts two arguments?

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Here is a function with two parameters, param1 and param2:

function testFun(param1, param2) {
  console.log(param1, param2);
}
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thanks. so how do I create a functionWithArgs(1,2) should output 3?

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You cannot really " create a functionWithArgs(1,2) should output 3?"

You can’t mix together sentences in the instructions like that.

Create a function called functionWithArgs that accepts two arguments and outputs their sum to the dev console.

Call the function with two numbers as arguments.

Creating and calling the function are two separate instructions

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that was the instruction?

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No, it was not. You cannot mix together the sentences like that.

The test said only

functionWithArgs(1,2) should output 3.

Creating a function and calling a function are different things.

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  1. Create a function called functionWithArgs that accepts two arguments and outputs their sum to the dev console.
  2. Call the function with two numbers as arguments.

this was the instruction

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And this was not an instruction. You mixed together two sentences in a way that doesn’t work.

This here is an example of creating a function.

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function functionWithArgs(1 + 2) {

console.log(1 + 2);

}

function functionWithArgs(7 + 9) {

console.log(7 + 9);

}

functionWithArgs

Above is what I was able to come up with.

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Did this example of creating a function use numbers? nope, it didn’t!

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function functionWithArgs(one, two) {

console.log(one, two);

}

function functionWithArgs(seven, nine) {

console.log(seven, nine);

}

functionWithArgs

Done this but still not successful

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Now the issue is that you defined the function twice. You must only have one function definition

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function functionWithArgs(one, two) {
console.log(seven, nine);
}

functionWithArgs

Kindly be patient with me mate. I can do this, I believe.

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This is a single function definition, but you have to use the function parameters ‘one’ and ‘two’. The variables ‘seven’ and ‘nine’ are not defined

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firstly, how do I use the function parameters ‘one’ and ‘two’ and how do I define the variables ‘seven’ and ‘nine’?

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You should not definite the variables ‘seven’ and ‘nine’. You should not use the variables ‘seven’ and ‘nine’ at all.

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function functionWithArgs(one, two) {
console.log(one, two);
}

functionWithArgs

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Closer, the function definition looks ok. But you aren’t calling the function correctly