Basic JavaScript - Stand in Line

JavaScript
1

I don’t know what I’m doing wrong.
arr.shift( ); keeps returning 6.

  **Your code so far**

function nextInLine(arr, item) {
// Only change code below this line

return item;
// Only change code above this line
arr.push(item);
return arr.shift();

}

// Setup
const testArr = [1, 2, 3, 4, 5];

// Display code
console.log("Before: " + JSON.stringify(testArr));
console.log(nextInLine(testArr, 6));
console.log("After: " + JSON.stringify(testArr));



  **Your browser information:**

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/105.0.0.0 Safari/537.36

Challenge: Basic JavaScript - Stand in Line

Link to the challenge:

2

You are not returning arr.shift()

You are returning item

3

Thanks for your help, but I honestly don’t understand.

4

Your function has two return statements inside it

Whe the first one is fired - full stop, all lower code inside function will not be executed

1 Like
5

Thanks, but I’m still confused.

6

Turns out I was writing the correct code in the wrong place. Thanks for your help.

7

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