Basic JavaScript - Use the parseInt Function

JavaScript
1

not sure what I have done.

Your code so far

var a =parseInt();
function convertToInteger(str) 
{
  
  return parseInt(str);
}

convertToInteger("56");
console.log(parseInt)

Your browser information:

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Challenge: Basic JavaScript - Use the parseInt Function

Link to the challenge:

2

Please click the reset button.

This time do not erase the function provided to you. Just add code to it without erasing anything.

1 Like
3

thanks done it bro thanks for advice

1 Like
4

The parseInt() method takes an argument. If a argument passed is a string and a number i.e.parseInt("56"); It will return integer 56. And if a argument passed is a string and not a number i.e. parseInt("Some text"); It will return NaN. Which means Not a number.

Solution:
Mod Edit: SOLUTION REMOVED

5

It is great that you solved the challenge, but instead of posting your full working solution, it is best to stay focused on answering the original poster’s question(s) and help guide them with hints and suggestions to solve their own issues with the challenge.

We are trying to cut back on the number of spoiler solutions found on the forum and instead focus on helping other campers with their questions and definitely not posting full working solutions.

6

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