Build a Leap Year Calculator - Build a Leap Year Calculator

JavaScript
1

Tell us what’s happening:

Can someone help with test ten it says I should store the result of calling the function in a variable called result. Thank you
let year = “”;

function isLeapYear(year) {
if (year % 400 === 0) {
return ${year} is a leap year.;
}
else if (year % 100 === 0) {
return ${year} is not a leap year.;
}
else if (year % 4 === 0) {
return ${year} is a leap year.;
}
else {
return ${year} is not a leap year.;
}
}
const result = isLeapYear();
console.log(result);

Your code so far

let year = "";

function isLeapYear(year) {
  if (year % 400 === 0) {
    return `${year} is a leap year.`;
  }
  else if (year % 100 === 0) {
    return `${year} is not a leap year.`;
  }
  else if (year % 4 === 0) {
    return `${year} is a leap year.`;
  }
  else {
    return `${year} is not a leap year.`;
  }
}

const result = isLeapYear();
console.log(result);

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/138.0.0.0 Safari/537.36

Challenge Information:

Build a Leap Year Calculator - Build a Leap Year Calculator
https://www.freecodecamp.org/learn/full-stack-developer/lab-leap-year-calculator/build-a-leap-year-calculator

2

Hi @A.M.Mutiso and welcome to our community!

Note these two User Stories:

Outside the function, declare a variable year that stores the value of the year you want to check.

You should call the isLeapYear function with year as the argument and assign the result to a variable named result.

You have declared a year variable but you haven’t assigned a suitable value to it.
You have called the isLeapYear function but you haven’t supplied an argument to it.

3

Look at what you’re initializing to the const result variable, it’s isLeapYear(), right?
Then look at your function isLeapYear(year) again, what’s missing?