Build a Leap Year Calculator - Build a Leap Year Calculator

JavaScript
1

Tell us what’s happening:

  1. With 2024 as the value of the year variable, the result should be 2024 is a leap year..
    Failed:6. With 2000 as the value of the year variable, the result should be 2000 is a leap year..
    Failed:7. With 1900 as the value of the year variable, the result should be 1900 is not a leap year..

can see results are ok to me but still these above points not passing.

Your code so far

function isLeapYear(year) 
{
if (year%4==0 && year%400==0 || year%100!=0 &&year%4==0) 
{
   return `${year} is a leap year;`
}
else 
{
   return `${year} is not a leap year;`
}
}
let year=2024;
let result=isLeapYear(year);
console.log(result);

year=2000;
result=isLeapYear(year);
console.log(result);

year=1900;
result=isLeapYear(year);
console.log(result);

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/144.0.0.0 Safari/537.36 Edg/144.0.0.0

Challenge Information:

Build a Leap Year Calculator - Build a Leap Year Calculator

2

You have simply two typos in the end of the returned values.

Seems like an accident. Have you wrote the syntax first and than added the backsticks?

3

not sure what u saying sorry, I tried to add those sticks again but still same.

4

Sorry for misleading you with my question.

You just have to make sure the are dots . at the end of the sentences.
Tests are looking for 100% string match.

1 Like
5

aaa got it never thought of that tiny mistake. Its gone thru. Many Thanks:)

1 Like