Build a Number Pattern Generator - Build a Number Pattern Generator

Python
1

Tell us what’s happening:

Greetings
my code seems to not pass the 2 condition statements(if statements) idk what could be the problem? any suggestions

Your code so far


def number_pattern(n):
    for i in range(1, n+1):
        if not isinstance(n, int):
            return 'Argument must be an integer value.'
        if n < 1:
            return 'Argument must be an integer greater than 0.'
       
        return ' '.join(str(i) for i in range(1, n+1))

print(number_pattern(10))

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Challenge Information:

Build a Number Pattern Generator - Build a Number Pattern Generator

2

Have you looked at some example cases for failing tests? For example, you can add at the bottom of code:

print(number_pattern('not a number'))
print(number_pattern(-5))
3

yeah i just checked it just returns none

4

solved it my if statements had to come before the for loop