Build an Arithmetic Formatter Project - Build an Arithmetic Formatter Project

Python
1

Tell us what’s happening:

I am unable to find what’s wrong here. The output is showing as asked.

Your code so far

def arithmetic_arranger(problems, show_answers=False):
    if len(problems) > 5:
        return print("Error: Too many problems.")
    
    top_row = ""
    bottom_row = ""
    dashes = ""
    result = ""

    for problem in problems:
        num1, operator, num2 = problem.split()     
        if operator not in ('+', '-'):
            return print("Error: Operator must be '+' or '-'")
        
        if not num1.isdigit() or not num2.isdigit():
            return print('Error: Numbers must only contain digits.')

        if max(len(num1), len(num2)) > 4:
            return print('Error: Numbers cannot be more than four digits.')
        
        top_row += " "*(2 + max(len(num1), len(num2))-len(num1)) + num1 + " "*4
        
        bottom_row += operator + " "*(1 + max(len(num1), len(num2))-len(num2)) + num2 + " "*4
        
        dashes += '-'*(2+max(len(num1), len(num2))) + " "*4
                
        if operator == '+':
            result += " "*2 + str(int(num1) + int(num2)) + " "*4
        else:
            result += " "*2 + str(int(num1) - int(num2)) + " "*4
            
    return print(f'{top_row[:-4]}\n{bottom_row[:-4]}\n{dashes}\n{result[:-4]}')

arithmetic_arranger(["32 + 698", "3801 - 2", "45 + 43", "123 + 49"])

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Challenge Information:

Build an Arithmetic Formatter Project - Build an Arithmetic Formatter Project

2

Have you looked at what arithmetic_arranger returns? Try wrapping the function call with the print function to see what it returns:

print(arithmetic_arranger(["32 + 698", "3801 - 2", "45 + 43", "123 + 49"]))
3

I have tried with same code but it showing “None”.

4

Then that’s what function returns. Per specification arithmetic_arranger should return string with arranged problems.

5

I got what what wrong thanks to you. But, now when I give with result it uncheck questions without result. what to do. New Code:

def arithmetic_arranger(problems):
    if len(problems) > 5:
        return "Error: Too many problems."
    
    top_row = ""
    bottom_row = ""
    dashes = ""
    result = ""

    for problem in problems:
        num1, operator, num2 = problem.split()     
        if operator not in ('+', '-'):
            return "Error: Operator must be '+' or '-'."
        
        if not num1.isdigit() or not num2.isdigit():
            return 'Error: Numbers must only contain digits.'

        if max(len(num1), len(num2)) > 4:
            return 'Error: Numbers cannot be more than four digits.'
        
        top_row += " "*(2 + max(len(num1), len(num2))-len(num1)) + num1 + " "*4
        
        bottom_row += operator + " "*(1 + max(len(num1), len(num2))-len(num2)) + num2 + " "*4
        
        dashes += '-'*(2+max(len(num1), len(num2))) + " "*4
                
        if operator == '+':
            result += " "*2 + str(int(num1) + int(num2)) + " "*4
        else:
            result += " "*2 + str(int(num1) - int(num2)) + " "*4

    return f'{top_row[:-4]}\n{bottom_row[:-4]}\n{dashes[:-4]}'
    
print(arithmetic_arranger(["32 + 698", "3801 - 2", "45 + 43", "123 + 49"]))

print(arithmetic_arranger(["11 + 4", "3801 - 2999", "1 + 2", "123 + 49", "1 - 9380"]))
6

What do you mean with this?
what’s happening now?

I’ve edited your code for readability. When you enter a code block into a forum post, please precede it with a separate line of three backticks and follow it with a separate line of three backticks to make it easier to read.

You can also use the “preformatted text” tool in the editor (</>) to add backticks around text.

Pre-formatted-text
Pre-formatted-text1356×380 401 KB

See this post to find the backtick on your keyboard.
Note: Backticks (`) are not single quotes (').

7

I am trying to say that my all requirements are fulfilled except the last two, where we are require to print with the calculated answers of the given data. but if i add the program with calculated answer (result) it uncheck the other requirements where it was not needed to print.

Screenshot 2025-02-12 160304
Screenshot 2025-02-12 160304452×472 64.7 KB

8

Function needs to handle both cases, depending on the second argument passed to function.

9

Thanks bro or sis, I had completely forget about this parameter at later stages. I have completed the project. Thanks for all your help

1 Like