Callback function confusion, Seek and Destroy

JavaScript
1

The first array is filtered in a search for arr elements that not found in targets. It seems that filter is not working. What is incorrect?

function destroyer(array, ...iv) {
  let targets = [...iv];
  let arr = [...array];
  arr.filter(element => {
    return !arr.indexOf(element);
  });
  return arr;
}
 destroyer([1, 2, 3, 1, 2, 3], 2, 3);

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Challenge: Seek and Destroy

Link to the challenge:

2

The return part of the callback can search targets.
return !targets.indexOf(element);

3

.filter() does not modify the array. It returns a new array.
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/filter

4

Thank you. Let me rework something.

5 
function destroyer(array, ...iv) {
  let targets = [...iv];
  let arr = [...array];
  let result = arr.filter(element => {
    return targets.indexOf(element) === -1;
  });
  return result;
}
 destroyer([1, 2, 3, 1, 2, 3], 2, 3);

Pikachu accepts me! I have at last made my own solution for this challenge.

6

I’ve edited your post for readability. When you enter a code block into a forum post, please precede it with a separate line of three backticks and follow it with a separate line of three backticks to make it easier to read.

You can also use the “preformatted text” tool in the editor (</>) to add backticks around text.

Pre-formatted-text
Pre-formatted-text1356×380 401 KB

See this post to find the backtick on your keyboard.
Note: Backticks (`) are not single quotes (’).

7

Challenge Seek and Destroy
Learn Intermediate Algorithm Scripting: Seek and Destroy | freeCodeCamp.org

8

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