Tell us what’s happening:
I believe that the by_three function is not reading correctly.
Here are the instruction related to the exercise:
First, def a function called cube that takes an argument called number. Don’t forget the parentheses and the colon!
Make that function return the cube of that number (i.e. that number multiplied by itself and multiplied by itself once again).
Define a second function called by_three that takes an argument called number.
if that number is divisible by 3, by_three should call cube(number) and return its result. Otherwise, by_three should return False.
Don’t forget that if and else statements need a : at the end of that line!
the link for the exercise is here: click here
Your code so far
def cube(number): return number * number * number print cube(3) def by_three(number): if number % 3 == 0: return cube(number) else: return False print by_three(3)
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Link to the challenge: