Explain the use of the ‘nonlocal’ keyword in Python

Python
#1

For what purpose “NonLocal” keyword is used in Python?

#2

Hello,
Here is the answer to your query-
First, let’s discuss the local and global scope. By example, a variable defined inside a function is local to that function. Another variable defined outside any other scope is global to the function.
Suppose we have nested functions. We can read a variable in an enclosing scope from inside he inner function, but cannot make a change to it. For that, we must declare it nonlocal inside the function. First, let’s see this without the nonlocal keyword.

>>> def outer():
    a=7
    def inner():
        print(a)
    inner()
>>> outer()
7
```` >>> def outer():
    a=7
    def inner():
        print(a)
        a+=1
        print(a)
    inner()

outer()

File “<pyshell#462>”, line 1, in <module> 
outer()
File “<pyshell#461>”, line 7, in outer
inner() 
File “<pyshell#461>”, line 4, in inner 
print(a)
UnboundLocalError: local variable ‘a’ referenced before assignment.
So now, let’s try doing this with the ‘nonlocal’ keyword:

>>> def outer():
    a=7
    def inner():
        nonlocal a
        print(a)
        a+=1
        print(a)```
inner()

outer()