Intermediate Algorithm Scripting - Sorted Union

Curriculum Help
1

Tell us what’s happening:

Describe your issue in detail here.

Your code so far

function uniteUnique(arr) {
  const rest = [...arguments];
  const result = [];
  for (let i = 0; i < rest.length; i++) {
  for (let j = 0; j < rest[i]; i++) {
    if (!result.includes(rest[i][j])) {
  result.push(rest[i][j]);
    }
  }
  }
  return result;
}

uniteUnique([1, 3, 2], [5, 2, 1, 4], [2, 1]);

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Challenge Information:

Intermediate Algorithm Scripting - Sorted Union
https://www.freecodecamp.org/learn/javascript-algorithms-and-data-structures/intermediate-algorithm-scripting/sorted-union**what’s wrong**

2

Hi, did you have an error message or question about this problem?

3

What did you try?
What isn’t working properly?
Is there an error?
Did you check the console for messages?
Trying using console.log() to print your variables and see what’s happening.

4

TypeError: Cannot read properties of undefined (reading ‘length’)

5

I don’t get that error with your code. However the function is returning []

Add some console.log() in there to see what’s happening. Try this:

function uniteUnique(arr) {
  const rest = [...arguments];
  const result = [];
  for (let i = 0; i < rest.length; i++) {
    console.log(i)
    console.log(rest[i])
  for (let j = 0; j < rest[i]; i++) {
    console.log(j)
    if (!result.includes(rest[i][j])) {
  result.push(rest[i][j]);
    }
  }
  }
  return result;
}