Hey could you explain why does my code not work? I cant come up with an idea to solve it…
Your code so far
function filteredArray(arr, elem) {
let newArr = [];
// change code below this line
for (let i = 0; i < arr.length; i++) {
for (let j = 0; j < arr[i].length; j++) {
if (arr[i][j] == elem) {
arr[i].splice(i, 1);
}
}
newArr.push(arr[i]);
}
// change code above this line
return newArr;
}
// change code here to test different cases:
console.log(filteredArray([[3, 2, 3], [1, 6, 3], [3, 13, 26], [19, 3, 9]], 3));
Your browser information:
User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/70.0.3538.102 Safari/537.36.
Consider a slightly different approach, perhaps. Yes, use that outer for loop, to iterate over each sub-array, but is there a way to see if a given element exists in an array WITHOUT having to loop over that whole array? Hint, take a look at indexOf(…).
Inside your i loop, consider simply checking if elem is in arr[i]. If it is NOT, then push arr[i] onto your newArr.
Here’s the tricky bit – how do you check for the non-existence of elem in arr[i], in a single statement?
function filteredArray(arr, elem) {
let newArr = [];
// change code below this line
for (let i = 0; i < arr.length; i++) {
if (arr[i].indexOf(elem) == -1) {
newArr.push(arr[i]);
}
}
// change code above this line
return newArr;
}
// change code here to test different cases:
console.log(filteredArray([[3, 2, 3], [1, 6, 3], [3, 13, 26], [19, 3, 9]], 3));