# Iterate Through All an Array&#x27;s Items Using For Loops help pls

Tell us what’s happening:

Hey could you explain why does my code not work? I cant come up with an idea to solve it…

``````
function filteredArray(arr, elem) {
let newArr = [];
// change code below this line
for (let i = 0; i < arr.length; i++) {
for (let j = 0; j < arr[i].length; j++) {
if (arr[i][j] == elem) {
arr[i].splice(i, 1);
}
}
newArr.push(arr[i]);
}

// change code above this line
return newArr;
}

// change code here to test different cases:
console.log(filteredArray([[3, 2, 3], [1, 6, 3], [3, 13, 26], [19, 3, 9]], 3));
``````

User Agent is: `Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/70.0.3538.102 Safari/537.36`.

Consider a slightly different approach, perhaps. Yes, use that outer for loop, to iterate over each sub-array, but is there a way to see if a given element exists in an array WITHOUT having to loop over that whole array? Hint, take a look at indexOf(…).

Inside your `i` loop, consider simply checking if `elem` is in `arr[i]`. If it is NOT, then push `arr[i]` onto your `newArr`.

Here’s the tricky bit – how do you check for the non-existence of `elem` in `arr[i]`, in a single statement?

1 Like

Hey, first of all thanks for help.

I edited my code to look like this:

``````
function filteredArray(arr, elem) {
let newArr = [];
// change code below this line
for (let i = 0; i < arr.length; i++) {
if (arr[i].indexOf(elem) == -1)  {
newArr.push(arr[i]);
}
}

// change code above this line
return newArr;
}

// change code here to test different cases:
console.log(filteredArray([[3, 2, 3], [1, 6, 3], [3, 13, 26], [19, 3, 9]], 3));

``````
1 Like

Word of advice, though – when you post a working solution, wrap it in a spoiler tag (found under the gear menu, for this reply editor).