this problem how can i solve with for loop not use a built-in function

```
let array = [
[1,2,3],
[4,5,6],
[7,8,9],
[[10,11,12],13,14],
[[15,16,16],[17,18,[19,20]]]
]
```

this problem how can i solve with for loop not use a built-in function

```
let array = [
[1,2,3],
[4,5,6],
[7,8,9],
[[10,11,12],13,14],
[[15,16,16],[17,18,[19,20]]]
]
```

Something like this using recursion.

```
function flatForEach(arg, f) {
if (!Array.isArray(arg)) {
return f(arg);
}
for (const element of arg) {
flatForEach(element, f);
}
}
flatForEach(array, console.log);
```

1 Like

i need to just for loop way not any recursive or built-in function

is it possible

No it’s not possible without recursion unless you can guarantee how many dimensions there are.

Here’s one that works for four dimensions or less. It’s ugly and I don’t support anyone using it.

```
function fourDimensionalForEach(array, f) {
for (const first of array) {
if (Array.isArray(first)) {
for (const second of first) {
if (Array.isArray(second)) {
for (const third of second) {
if (Array.isArray(third)) {
for (const fourth of third) {
f(fourth);
}
} else {
f(third);
}
}
} else {
f(second);
}
}
} else {
f(first);
}
}
}
fourDimensionalForEach(array, console.log);
```

thank for details explain to me