Learn Interfaces by Building an Equation Solver - Step 27

Tell us what’s happening:

i don’t know how to fit the intercept and slope into this, i get name error or atrribute error whenever i try to do so, this is the only time where i don’t get an error

``````from abc import ABC, abstractmethod

class Equation(ABC):
degree: int

def __init__(self, *args):
if (self.degree + 1) != len(args):
raise TypeError(
f"'Equation' object takes {self.degree + 1} positional arguments but {len(args)} were given"
)
if any(not isinstance(arg, (int, float)) for arg in args):
raise TypeError("Coefficients must be of type 'int' or 'float'")
if args[0] == 0:
raise ValueError("Highest degree coefficient must be different from zero")
self.coefficients = {(len(args) - n - 1): arg for n, arg in enumerate(args)}

def __init_subclass__(cls):
if not hasattr(cls, "degree"):
raise AttributeError(
f"Cannot create '{cls.__name__}' class: missing required attribute 'degree'"
)

def __str__(self):
terms = []
for n, coefficient in self.coefficients.items():
if not coefficient:
continue
if n == 0:
terms.append(f'{coefficient:+}')
elif n == 1:
terms.append(f'{coefficient:+}x')
equation_string = ' '.join(terms) + ' = 0'
return equation_string.strip('+')

@abstractmethod
def solve(self):
pass

@abstractmethod
def analyze(self):
pass

class LinearEquation(Equation):
degree = 1

def solve(self):
a, b = self.coefficients.values()
x = -b / a
return x

# User Editable Region

def analyze(self):
a,b = self.coefficients
return self.coefficients.keys()

lin_eq = LinearEquation(2, 3)
print(lin_eq)
print(lin_eq.solve())
print(lin_eq.analyze())

# User Editable Region

``````

User Agent is: `Mozilla/5.0 (Macintosh; Intel Mac OS X 10_15_7) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/128.0.0.0 Safari/537.36`

Challenge Information:

Learn Interfaces by Building an Equation Solver - Step 27

• Use the same method as in `solve` to get the values `self.coefficients.values()`

• Store the two values returned in variables named `slope` and `intercept`

• Return a dictionary with the keys named the same as the two values and the two values as the values (e.g. `{ 'name' : name, 'age': age }`).

1 Like
``````from abc import ABC, abstractmethod

class Equation(ABC):
degree: int

def __init__(self, *args):
if (self.degree + 1) != len(args):
raise TypeError(
f"'Equation' object takes {self.degree + 1} positional arguments but {len(args)} were given"
)
if any(not isinstance(arg, (int, float)) for arg in args):
raise TypeError("Coefficients must be of type 'int' or 'float'")
if args[0] == 0:
raise ValueError("Highest degree coefficient must be different from zero")
self.coefficients = {(len(args) - n - 1): arg for n, arg in enumerate(args)}

def __init_subclass__(cls):
if not hasattr(cls, "degree"):
raise AttributeError(
f"Cannot create '{cls.__name__}' class: missing required attribute 'degree'"
)

def __str__(self):
terms = []
for n, coefficient in self.coefficients.items():
if not coefficient:
continue
if n == 0:
terms.append(f'{coefficient:+}')
elif n == 1:
terms.append(f'{coefficient:+}x')
equation_string = ' '.join(terms) + ' = 0'
return equation_string.strip('+')

@abstractmethod
def solve(self):
pass

@abstractmethod
def analyze(self):
pass

class LinearEquation(Equation):
degree = 1

def solve(self):
a, b = self.coefficients.values()
x = -b / a
return x
def analyze(self):
slope,intercept = self.coefficients.values()
return {'slope': a, 'intercept': b}

lin_eq = LinearEquation(2, 3)
print(lin_eq)
print(lin_eq.solve())
print(lin_eq.analyze())
``````

nvm done it, thanks man

also is it just me but these projects have got hard really quick