Learn Introductory JavaScript by Building a Pyramid Generator - Step 58

JavaScript
1

Tell us what’s happening:

I declared test variable inside the function. But it returns error. Please help me to get unstuck

Your code so far

const character = "#";
const count = 8;
const rows = [];


// User Editable Region

function padRow(name) {
  let test = "Testing";
  return character + name;
}
console.log(test)

// User Editable Region

const call = padRow("CamperChan");
console.log(call);


for (let i = 0; i < count; i = i + 1) {
  rows.push(character.repeat(i + 1))
}

let result = ""

for (const row of rows) {
  result = result + "\n" + row;
}

console.log(result);

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/126.0.0.0 YaBrowser/24.7.0.0 Safari/537.36

Challenge Information:

Learn Introductory JavaScript by Building a Pyramid Generator - Step 58

2

Hi there!

Pay intention to the instructions:
To see this in action, use const to declare a test variable in your padRow function. Initialise it with the value “Testing”.

1 Like
3

After using const to declare your variable, delete the console log to avoid a scope error.

1 Like
4

Thank you! I tried let and const! But I forget to delete console.log statement =)

5

Thank you! I forget to do it =)