Learn String Manipulation by Building a Cipher - Step 40

Python
1

Tell us what’s happening:

How to solve this code?, I try to use char valuable compare with space and print out but is error.

Your code so far


# User Editable Region

text = 'Hello World'
shift = 3
alphabet = 'abcdefghijklmnopqrstuvwxyz'
encrypted_text = ''

for char in text.lower():
    char == ''
    print (char == '')
    index = alphabet.find(char)
    new_index = index + shift
    encrypted_text += alphabet[new_index]
    print('char:', char, 'encrypted text:', encrypted_text)

# User Editable Region

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Challenge Information:

Learn String Manipulation by Building a Cipher - Step 40

2

Hi. You were asked to do the comparison inside the print log. No need for the first line you added.

Have a look at the instructions - you have missed something in your print comparison:

 comparing char with a space (' ')

Have you done a space?

3

I already do as you suggest but is error

text = 'Hello World'
shift = 3
alphabet = 'abcdefghijklmnopqrstuvwxyz'
encrypted_text = ''

for char in lower.alphabet()
    print (char == '  ')
    index = alphabet.find(char)
    new_index = index + shift
    encrypted_text += alphabet[new_index]
    print('char:', char, 'encrypted text:', encrypted_text)
4

those spaces is not the same as one space

I’ve edited your post to improve the readability of the code. When you enter a code block into a forum post, please precede it with a separate line of three backticks and follow it with a separate line of three backticks to make it easier to read.

You can also use the “preformatted text” tool in the editor (</>) to add backticks around text.

Pre-formatted-text
Pre-formatted-text1356×380 401 KB

See this post to find the backtick on your keyboard.
Note: Backticks (`) are not single quotes (').