Learn String Manipulation by Building a Cipher - Step 41

Python
1

Tell us what’s happening:

I don’t understand what is wrong. When this code is ran FCC’s hint suggests putting the string ‘space!’ inside my statement.
When I replace this if statement with:
if char == ‘space!’:
FCC will suggest I go about having char == ’ ': in my if statement.
Confused here

Your code so far


# User Editable Region

text = 'Hello World'
shift = 3
alphabet = 'abcdefghijklmnopqrstuvwxyz'
encrypted_text = ''
for char in text.lower():
        if char == ' ':
            print(char)
    index = alphabet.find(char)
    new_index = index + shift
    encrypted_text += alphabet[new_index]
    print('char:', char, 'encrypted text:', encrypted_text)

# User Editable Region

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/127.0.0.0 Safari/537.36

Challenge Information:

Learn String Manipulation by Building a Cipher - Step 41

2

Hi @pck3t,

Double-check the instructions. The instructions wants print('space!') inside the if block, not in the if’s condition.

if x < y:
    // code inside the if block
    print('hello')

Make sure you indent properly as well.

I hope this helps. Happy coding!

1 Like