Learn String Manipulation by Building a Cipher - Step 42

Sorry, your code does not pass. Don’t give up.

You should replace print(char == ' ') with an if statement that triggers when char == ' '. Do not use parentheses to enclose the if condition.
i don’t know what im doing wrong

Your code so far


# User Editable Region

text = 'Hello World'
shift = 3
alphabet = 'abcdefghijklmnopqrstuvwxyz'
encrypted_text = ''

for char in text.lower():
    if char == 'space!':
        print(char)
    index = alphabet.find(char)
    new_index = index + shift
    encrypted_text += alphabet[new_index]
    print('char:', char, 'encrypted text:', encrypted_text)

# User Editable Region

Your browser information:

User Agent is: Mozilla/5.0 (Macintosh; Intel Mac OS X 10_15_7) AppleWebKit/605.1.15 (KHTML, like Gecko) Version/17.2.1 Safari/605.1.15

Challenge Information:

Learn String Manipulation by Building a Cipher - Step 42

If the variable char is equal to a space ' ' then you should print the string 'space!'

Your code checks if char is equal to 'space!' and prints char

thank you!!
It’s still wrong though…

Please share your updated code