Learn String Manipulation by Building a Cipher - Step 42

Python
1

Tell us what’s happening:

I’ve checked other questions but they don’t seem to be different to mine. What’s wrong with it?

Your code so far


# User Editable Region

text = 'Hello World'
shift = 3
alphabet = 'abcdefghijklmnopqrstuvwxyz'
encrypted_text = ''

for char in text.lower():
    if char == ' ':
        print('space!')
    index = alphabet.find(char)
    new_index = index + shift
    encrypted_text += alphabet[new_index]
    print('char:', char, 'encrypted text:', encrypted_text)

# User Editable Region

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Challenge Information:

Learn String Manipulation by Building a Cipher - Step 42

2

What does the error message say? Where have you gotten stuck trying to fix it?

3

This doesn’t look like printing the result of comparing the char to a single space. You do the comparison, but you don’t actually print the result of the comparison itself.

5

What do you mean? Sorry for not understanding, but isn’t what I’m doing printing ‘space!’ if the result of the comparison is True?

6

Yes, you are printing “Space!”. You are not

print[ing] the result of comparing char with a space (' ').

7

Are you saying I should phrase it like this?

if char == ' ':
        print(char == ' ')
8

Closer, but you don’t need to guard the print statement with an if. Your second line, properly indented, is all you need.

9

Ah, thank you. I’ve got it working now. Thanks for helping me!

1 Like
10

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