# Learn String Manipulation by Building a Cipher - Step 42

### Tell us what’s happening:

can anyone help me i can’t get the if statement to work

``````
# User Editable Region

text = 'Hello World'
shift = 3
alphabet = 'abcdefghijklmnopqrstuvwxyz'
encrypted_text = ''
if char == ' ':

print(space!)
for char in text.lower():
index = alphabet.find(char)
new_index = index + shift
encrypted_text += alphabet[new_index]
print('char:', char, 'encrypted text:', encrypted_text)

# User Editable Region

``````

User Agent is: `Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/120.0.0.0 Safari/537.36`

### Challenge Information:

Learn String Manipulation by Building a Cipher - Step 42

You appear to have created this post without editing the template. Please edit your post to Tell us what’s happening in your own words.

Welcome to the forum @NoumiHacker

The if statement and print call should be in the loop body.
Don’t forget that your print call is for a string.

Happy coding

``````text = 'Hello World'
shift = 3
alphabet = 'abcdefghijklmnopqrstuvwxyz'
encrypted_text = ''

for char in text.lower():
if char == ' '
print(space!)
index = alphabet.find(char)
new_index = index + shift
encrypted_text += alphabet[new_index]
print('char:', char, 'encrypted text:', encrypted_text)
``````

cud some1 explain to me y this is wongg
thnks <3

Solution removed by moderator

It is great that you solved the challenge, but instead of posting your full working solution, it is best to stay focused on answering the original poster’s question(s) and help guide them with hints and suggestions to solve their own issues with the challenge.

We are trying to cut back on the number of spoiler solutions found on the forum and instead focus on helping other campers with their questions and definitely not posting full working solutions.

your space! should be in (’ ')

if char==’ ':print(‘space!’)

What is wrong here?

Please open a new topic, thanks

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Thank you.