Learn string manipulation by building a cipher step 47

Python
1

here’s my code so far:

text = 'Hello Zaira'
shift = 3
alphabet = 'abcdefghijklmnopqrstuvwxyz'
encrypted_text = ''

for char in text.lower():
    if char == ' ':
        encrypted_text += char
    else:
        index = alphabet.find(char)
        new_index = (index + shift) % len(alphabet)
        encrypted_text += alphabet[new_index]
    print('char:', char, 'encrypted text:', encrypted_text)

what to do???

2

I’ve edited your code for readability. When you enter a code block into a forum post, please precede it with a separate line of three backticks and follow it with a separate line of three backticks to make it easier to read.

You can also use the “preformatted text” tool in the editor (</>) to add backticks around text.

Pre-formatted-text
Pre-formatted-text1356×380 401 KB

See this post to find the backtick on your keyboard.
Note: Backticks (`) are not single quotes (').

It’s also helpful to include a link to the challenge (which I have now added for you). In future you can simply click on the Help button, which appears after you have submitted incorrect code three times.

This will create a forum post which automatically includes your full code, a link to the challenge and an opportunity for you to describe your issue in detail.

3

Next, modify your print() call to print 'encrypted text:', encrypted_text and put it outside the for loop, so that the encrypted string is printed one time.

So, modify this print call accordingly:

print('char:', char, 'encrypted text:', encrypted_text)

To move it outside of the for loop, it just needs to have its indentation changed. (It is currently indented into the for loop, so is part of its body).