Learn String Manipulation by Building a Cipher - Step 50

Python
1

Tell us what’s happening:

can anyone help me it is showing me some indent error and not able to get it

Your code so far

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text = 'Hello Zaira'
shift = 3
def caesar ():
        alphabet = 'abcdefghijklmnopqrstuvwxyz'
        encrypted_text = ''
        for char in text.lower():
            if char == ' ':
                encrypted_text += char
            else:
                index = alphabet.find(char)
                new_index = (index + shift) % len(alphabet)
                encrypted_text += alphabet[new_index]    
        print('plain text:', text)
        print('encrypted text:', encrypted_text)
caesar()

Challenge Information:

Learn String Manipulation by Building a Cipher - Step 50

2

You should indent all the lines after shift = 3 so that they become your new function body.

You are missing one line, the last line of code is not indented

3

made changes but still not able to solve without calling function

4

I’ve edited your code for readability. When you enter a code block into a forum post, please precede it with a separate line of three backticks and follow it with a separate line of three backticks to make it easier to read.

You can also use the “preformatted text” tool in the editor (</>) to add backticks around text.

Pre-formatted-text
Pre-formatted-text1356×380 401 KB

See this post to find the backtick on your keyboard.
Note: Backticks (`) are not single quotes (').

1 Like
5

with or without the function call your code passes, the function call is irrelevant for the tests

1 Like
6

Thankyou for considering my request

7

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