Palindrome Checker prob

Tell us what’s happening:
palindrome(“1 eye for of 1 eye.”) should return false.
why it should ???
You’ll need to !!!remove!!! all non-alphanumeric characters (punctuation, !!!spaces!!! and symbols) and turn everything into the same case (lower or upper case) in order to check for palindromes.

Your code so far

function palindrome(str) {
    let filtred = str.toLowerCase().split('').filter(a=>a.charCodeAt(0)>96&&a.charCodeAt(0)<123).join('');
    return filtred.split('').reverse().join('') == filtred;


Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 6.1; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/67.0.3396.87 Safari/537.36.

Link to the challenge:

“1eyeforof1eye” is not the same as “eye1forofeye1”

oh thx i have missed all non-alphaNUMERIC characters