Passing Values to Functions with Arguments

[mandeep-s1ngh]

Hi There, I was stuck on this challenge and ended up having to copy/paste the solution from the video which worked however I am not sure if it is a bug or I am just not understanding the code properly but struggling to see where 3 and 16 come from.

function functionWithArgs(a, b) {
    console.log(a + b);
}

functionWithArgs(10, 5)

[skaparate]

Hello! Welcome to the community !

@mandeep-s1ngh

struggling to see where 3 and 16 come from

Those values come from the parameters you pass to the function when you call it.

On this line functionWithArgs(10, 5) you’re calling the function and passing two parameters: 10 and 5

These parameters (10 and 5) are assigned to the variables a and b on the definition of the function here:

function functionWithArgs(a, b) {
    // At this point, a = 10 and b = 5
    console.log(a + b);
}

Does it help?

Check this out if my explanation doesn’t help: click here.

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Also:

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[mandeep-s1ngh]

Hi, thank you for replying however the tests on the challenge compared the output of the code do not match. I am unsure where 3 and 16 are being picked up from.

[skaparate]

Ah! I see!

The tests call the function at lest two times:

1. The function is called with the parameters 1 and 2 (a = 1, b =2), where 1 + 2 equals 3
2. The function is called with the parameters 7 and 9 (a = 7, b = 9), where 7 + 9 equals 16

That explains the output of 3 and 16. The first 15, if you’re wondering, is from the parsing of the script, which includes the first call to your function as defined here:

function functionWithArgs(a, b) {
    console.log(a + b);
}

functionWithArgs(10, 5) // <-- First call

That’s why you see 15, 3 and 16 in the console.

[mandeep-s1ngh]

right, so having gone through it out loud multiples, it is starting to make sense now. thank you for your help.

[skaparate]

No problem, we’re happy to help !

Happy coding!