function functionWithArgs(param1, param2){
functionWithArgs(1,2);
console.log();
}
i’m unable to understand this
-
functionWithArgs(1,2)should output3. -
Failed:
functionWithArgs(7,9)should output16.
function functionWithArgs(param1, param2){
functionWithArgs(1,2);
console.log();
}
i’m unable to understand this
functionWithArgs(1,2) should output 3.
Failed:functionWithArgs(7,9) should output 16.
Basically you need to create a function called functionWithArgs.
Then, fill in the logic to output the sum. Also add a line to console.log it out!
Then, call a function once e.g. functionWithArgs(1,2)
function functionWithArgs(aa1, aa2){
console.log(1+2, 7+9);
}
functionWithArgs(3,16);
}
functionWithArgs()
functionWithArgs(7,9) should output 16 .
What more improvements i have to do?
i think you should NOT have TWO functions as solution.
You can try add in this at bottom,
functionWithArgs(1,2)
functionWithArgs(7,9)
then look at the console output.
Are they 3 and 16?
If not, you need to modify this line:
console.log(1+2, 7+9);
Try replace with you argument of aa1 and aa2.
Sometimes, i read extra reference to understand more >>> JavaScript Functions
function functionWithArgs(aa1,aa2){
console.log(aa1+aa2);
}
functionWithArgs(3,16);
code successfully submitted with the above solution.