Tell us what’s happening:
Hi,
i have checked the hint and i understand the concept behind it. My solution was longer than the one provided. It works for the first element (object) in the array, but it doesn’t loop to the next element. Kindly help me understand where i am getting this wrong.
**Your code so far**
// Setup
var contacts = [
{
"firstName": "Akira",
"lastName": "Laine",
"number": "0543236543",
"likes": ["Pizza", "Coding", "Brownie Points"]
},
{
"firstName": "Harry",
"lastName": "Potter",
"number": "0994372684",
"likes": ["Hogwarts", "Magic", "Hagrid"]
},
{
"firstName": "Sherlock",
"lastName": "Holmes",
"number": "0487345643",
"likes": ["Intriguing Cases", "Violin"]
},
{
"firstName": "Kristian",
"lastName": "Vos",
"number": "unknown",
"likes": ["JavaScript", "Gaming", "Foxes"]
}
];
function lookUpProfile(name, prop) {
// Only change code below this line
for (var i = 0; i < contacts.length; i++) {
if (contacts[i]["firstName"] === name && contacts[i].hasOwnProperty(prop) === true) {
return contacts[i][prop];
} else if (contacts[i]["firstName"] !== name) {
return 'No such contact';
} else if (contacts[i].hasOwnProperty(prop) !== true) {
return 'No such property';
} else {
return 'kindly enter valid details';
}
}
// Only change code above this line
}
lookUpProfile("Akira", "likes");
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@Wairua, This is all happening because of your if-else conditions.
so when you call lookUpProfile("Akira", "likes"); for “Akira” it goes inside first if statement and checks for the first element and as first element name is same as that of what name you are passing in, so it executes the code inside that if and returns likes array.
Now, check for the another call lookUpProfile("Harry", "likes");, So here again on first if statement it checks, if the first name in the array ("Akira" here) matches with the name you have passed in ("Harry" here), but it fails as names doesn’t match, so then control goes to else statement and where there is an another if statement which identifies if name in the array ("Akira" here) is not equal to the name you passed in ("Harry" here), and as they are not equals control gets inside it and return ‘No Such Contact’.
Well, I am not able to understand the significance of your code but try to use map() method instead of for loop.
For first element it will never be true because it is inside else statement which doesn’t executes as its if condition will be true for the first element.
It is great that you solved the challenge, but instead of posting your full working solution, it is best to stay focused on answering the original poster’s question(s) and help guide them with hints and suggestions to solve their own issues with the challenge.
We are trying to cut back on the number of spoiler solutions found on the forum and instead focus on helping other campers with their questions and definitely not posting full working solutions.
You can post solutions that invite discussion (like asking how the solution works, or asking about certain parts of the solution). But please don’t just post your solution for the sake of sharing it.
If you post a full passing solution to a challenge and have questions about it, please surround it with [spoiler] and [/spoiler] tags on the line above and below your solution code.
I don’t understand what you are saying, the function is called with many different arguments, for some that is true for the first element in the array - for example if name equals "Harry" for the first element in the array it will be contacts[0]["firstName"] !== "Harry" or "Akira" !== "Harry" which is true
@ILM , I mean, when the function is being called like lookUpProfile("Akira", "likes"); this, then code inside first if statement will be executed (mentioned if statement below) and will get desired results.
if (contacts[i]["firstName"] === name && contacts[i].hasOwnProperty(prop) === true) {
return contacts[i][prop];
}
But, when the function call is given like lookUpProfile("Harry", "likes"); then below code will be execute.
if (contacts[i]["firstName"] === name && contacts[i].hasOwnProperty(prop) === true) {
return contacts[i][prop];
} else if (contacts[i]["firstName"] !== name) {
return 'No such contact';
}
It will check contacts[0]["firstName"] === "Harry" or "Akira" === "Harry" which is false, so if condition gets false and then control will move towards else if statement.
Now it will check contacts[0]["firstName"] !== "Harry" or "Akira" !== "Harry" which is true so it will execute the code inside it.
First apply condition for first name, then apply nested condition for non existence of property.
If name compare fails then apply condition to check the length of an array so that it will get to know that the array element are now completed but still no such name exists in array.
I think you choose a difficult approach to solve the issue. In programming it is often a good idea to divide a larger algorithm problem into smaller problems.
I suggest you divide your algorithm in those two parts:
(1) find the contact entry in the list that has the correct “firstName”. Save that matching contact entry to a local variable for example “matchinContact”.
If there is no contact entry that matches the required name => return “No such contact” before you continue with the next step.
(2) You found the correct contact entry in (1), the reference to the matching contact entry is saved in your local variable “matchingContact”. Now you can use the “hasOwnProperty” function or “in” operator to find out if “matchingContact” contains a property with the identifier “prop”.
If that you find such a property, return it.
If you don’t find such a property return “No such property” instead.
I hope this suggestions helps you, and keep coding!
‘Harry’ would be caught by the first condition in the if block (hence the if block will return the property if it exists) so the if else block won’t run