Return Early Pattern for Functions 3

JavaScript
1

Hello, can someone let me know what I need to put to make this code work? Thanks.

Your code so far


// Setup
function abTest(a, b) {
  // Only change code below this line
if (a || b < 0) {
return undefined
}
  
  
  // Only change code above this line

  return Math.round(Math.pow(Math.sqrt(a) + Math.sqrt(b), 2));
}

// Change values below to test your code
abTest(2,2);

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Link to the challenge:
https://learn.freecodecamp.org/javascript-algorithms-and-data-structures/basic-javascript/return-early-pattern-for-functions

2

what do you if you want to check if one of two numbers is equal to 2?
you can’t do num1 || num2 === 2 as it means “if num1 is truthy or num2 equals 2”
instead you need to check both numbers

3

From the syntax point of view, a ; should be present afterundefined

Here goes the solution that worked for me.
I hope it helps

function abTest(a, b) {
  // Only change code below this line
  
  if (a < 0 || b < 0) {
    return undefined;
  }