Return Early Pattern for Functions?

JavaScript
1

Tell us what’s happening:

I cannot understand how to make it return correctly

Your code so far


// Setup
function abTest(a, b) {
  // Only change code below this line
 a || b >=0;
  return undefined;
   
  
  // Only change code above this line

  return Math.round(Math.pow(Math.sqrt(a) + Math.sqrt(b), 2));
}

// Change values below to test your code
abTest(2,2);

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/70.0.3538.77 Safari/537.36.

Link to the challenge:
https://learn.freecodecamp.org/javascript-algorithms-and-data-structures/basic-javascript/return-early-pattern-for-functions

2

a || b >=0 by itself doesn’t mean anything.

you need to wrap that with an if statement.

eg
if (condition){return something}

also you need to define the conditions for a and b independently.

what you put there is basically saying something like…

if (a == a || b >= 0) which is probably not what you want

1 Like