Return Early Pattern for Functions pls help

JavaScript
1

Tell us what’s happening:

Your code so far


// Setup
function abTest(a, b) {
  // Only change code below this line
  console.log("a<0");
 
  return Math.round(Math.pow(Math.sqrt(a) + Math.sqrt(b), 2));
  return undefined
  
 
  
  
  // Only change code above this line


  
}


// Change values below to test your code
abTest(2,2);

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Link to the challenge:
https://learn.freecodecamp.org/javascript-algorithms-and-data-structures/basic-javascript/return-early-pattern-for-functions

2

You need to follow the instruction of only change code above/below this line or even if you give the right answer it will not pass

But that is not the right answer. You need to return undefined only if a or b are negative. And a return statement stop the code, so when a return statement is executed everything after that is not used. Your return undefined will not work because it is after an other return statement

3

convert this to JS code.

if a or b is less than 0 return undefined.

If you don’t understand what if-statements or return values are you can go back to some previous chapter.

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