# Return largest number in arrays.. don't know what went wrong

Return largest number in arrays.. don't know what went wrong
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#1

Can’t see what’s going wrong with this… it returns the correct numbers, can anyone help me out?

``````function largestOfFour(arr) {
var finalArr = [0,0,0,0];
var highest =0;

for(i=0; i<arr.length; i++){
for(j=0; j<arr[i][j]; j++){
if(arr[i][j]>=highest){
highest = arr[i][j];
finalArr[i] = highest;
}
}
}

return finalArr;
}

largestOfFour([[4, 5, 1, 3], [13, 27, 18, 26], [32, 35, 37, 39], [1000, 1001, 857, 1]]);
``````

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#2

`highest` is going to be the largest number found in the whole `arr`. You need to find the highest in each sub array.

#3

The current code already returns the largest number from each sub-array, that’s is why I don’t understand what is going wrong.

#4

For one, this statement here is incorrect:

`for(j=0; j<arr[i][j]; j++){`

I’m guessing that you want to loop through the size of each sub-array. The condition needs to be modified. The same idea you used with arr.length in the first loop is the key.

Other than that, it should work.

#5

For the array of largestOfFour, the next sub-array is larger than prev-array.
for(i=0; i<arr.length; i++){
highest = arr[i][0];
for(j=0; j<arr[i][j]; j++){
if(arr[i][j]>=highest){
highest = arr[i][j];
finalArr[i] = highest;
}
}
}