# Return Largest Numbers in Arrays - problem

Tell us what’s happening:
I can’t figure out why my code is not correct. Everything works fine but still FCC don’t want it. Anyone can explain what am I doing bad?

``````
function largestOfFour(arr) {
// You can do this!
let temp=0;
let final_arr=0;
let biggest=0;
console.log(Date.now());
console.log(arr);
arr.filter(ele => {
for(let i=0; i < ele.length; i++){
//console.log(ele);
if(ele[i] >= biggest){
biggest = ele[i];
final_arr = temp;
}
}
temp++;
});
console.log("arr[" + final_arr + "] = " + arr[final_arr]);
return arr[final_arr];
}

largestOfFour([[4, 5, 1, 3], [13, 27, 18, 26], [32, 35, 37, 39], [1000, 1001, 857, 1]]);
``````

User Agent is: `Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/69.0.3497.100 Safari/537.36`.

If you `console.log` your function you’ll see that you’re returning the last sub-array.

``````console.log(largestOfFour([[13, 27, 18, 26], [4, 5, 1, 3], [32, 35, 37, 39], [1000, 1001, 857, 1]]))
// returns [1000,1001,857,1] but expected [27, 5, 39, 1001]
``````

You should return the largest element of each sub-array.

1 Like

OMG… Sorry, I didn’t understand that task… I fixed it the lazy and awful way but it works and I think this is the most important in this case

``````function largestOfFour(arr) {
// You can do this!
let largest_arr = [-100,-100,-100,-100];
let temp = 0;
arr.filter(ele => {
for(let i = 0; i < ele.length; i++){
if(ele[i] > largest_arr[temp]) largest_arr[temp] = ele[i];
}
temp++;
});
return largest_arr;
}

largestOfFour([[4, 5, 1, 3], [13, 27, 18, 26], [32, 35, 37, 39], [1000, 1001, 857, 1]]);
``````