Seek and Destroy. confused by the argument

JavaScript
1

Tell us what’s happening:
Hi, the console here says that arr is 1,2,3,1,2,3. I thought it should be the 1, 2, 3, 1, 2, 3, 2, 3. Can someone tell me what have I misunderstood?

Your code so far


function destroyer(arr) {
  console.log(arr)
  return arr.filter(x => arr[0].includes(x) && !arr.includes(x));
}

destroyer([1, 2, 3, 1, 2, 3], 2, 3);

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/72.0.3626.121 Safari/537.36.

Link to the challenge:

2

ah I get it now, arguments is different from array. Thanks for clicking in guys.

3

The instructions are saying to use the arguments object. If you console.log(arguments) you’ll see the object containing all the info/data (arguments) being sent to the function.

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