[Solved] Arguments Optional (3/5 checked)

JavaScript
1

Tell us what’s happening:
| can’t seem to call another function. The problem facing addTogether(2)(3).

Cheers!
Your code so far


function addTogether() {
var arrNum = [];
for (let i = 0; i < arguments.length; i ++) {
  if (Number.isInteger(arguments[i])){
   arrNum.push(arguments[i]) 
   } else {
     return undefined;
   }
 }
 if (arrNum.length === 2)
 return arrNum.splice(0, 2).reduce((a, b) => a + b);
 else {
   return function(y){
   return + y;
 };
 } 
}

console.log(addTogether(2)(3));


// return [...arguments].reduce((a, c) => a + c);

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/80.0.3987.149 Safari/537.36.

Challenge: Arguments Optional

Link to the challenge:

2 
 else {
   return function(y){
   return + y;
 };
 }

Look what you are returning here. You should be return something added to y.

Assuming you figure out what should precede the + y above, the last test case addTogether(2)([3]), is probably going to be a problem with your current logic. It will depend on how you fix the above issue.

NOTE: Just remember that when you return the function, that function will need to validate that the argument passed is a number. You have no logic in the returned function that would perform this validation.

1 Like
3

Thanks! you’re clear and concise.

Here is the bottom half and how I have solved it:

  else {
    return function(y){
    if (Number.isInteger(y)){  
    arrNum.push(y)
    return arrNum.reduce((a, b) => a +b) }
    else {
      return undefined;
    }
  }
  } 
};

Thanks for the help, cheers!