Understanding undefined return with [] array

1

Tell us what’s happening: Hi! I’m trying to complete one of the challenges (Basic Algorithm Scripting: Where do I belong), and I have all conditions covered except where arr is an empty array []. As my code shows, I try to check for this first with an if statement, but instead the function returns “undefined” instead of 0. Every other conditions seems to work fine. I would appreciate any guidance for what I might be missing! I can think of some other ways to solve this challenge, but now I just really want to know what is wrong with what I have so far with the empty array check at the top. Thanks!

Your code so far


function getIndexToIns(arr, num) {
  if (arr == []) {
    return 0;
  } else {
    arr.sort((a, b) => a - b);
    for (let i = 0; i < arr.length; i++) {
      if (num > arr[arr.length-1]) {
        return arr.length;
      }
      if (num <= arr[i]) {
        return i;
      }
    }
  }
}

getIndexToIns([], 1);

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2

instead of “arr ==[]” or “arr===[]” i would put “arr.length === 0”.
This is beacause i think you do a reference comparision (related with positions in memory)