...Use the Rest Operator with Function Parameters

JavaScript
1

Tell us what’s happening:

my solution works but i want to understand how it works.

Your code so far


const sum = (function() {
  "use strict";
  return function sum(...args) {
    //const args = [ x, y, z ];
    return args.reduce((a, b) => a + b, 0);
  };
})();
console.log(sum(1, 2, 3)); // 6
console.log(sum(0,1,2));

Your browser information:

User Agent is: Mozilla/5.0 (Windows NT 6.3; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/72.0.3626.109 Safari/537.36.

Link to the challenge:
https://learn.freecodecamp.org/javascript-algorithms-and-data-structures/es6/use-the-rest-operator-with-function-parameters