Why the array is flatten in my function but it is returned as undefined?

JavaScript
1

Hi Guys,

So, i made this recursive function where i send again and again an array until it is flatten entirely. But, while my array gets nicely flatten in my function, when i return him outside the function to a varriable, when i log this variable, the result is ‘undefined’:

function flatArray (arr){
    let counter=0;
    //console.log(arr);
    for(let i=0;i<arr.length;i++){
        if(Array.isArray(arr[i])){
            arr=arr.flat();
            counter=0;
        }
        else{
            counter++;
        }
    }
    if(counter===arr.length){
        console.log(arr); // the arr here is nicely flattened
        return arr;
    }
    
    flatArray(arr);
}

let arr2 = [22,4,[5],5,[2,[2,[2,5,8]]]];
let x = flatArray(arr2);
console.log(x); // here the value is undefined

This gets me crazy! :smiley:

2

uhm, i foudn an article about this. I actually need to call the function with the return statement in front. so my code should be like this:

function flatArray (arr){
    let counter=0;
    //console.log(arr);
    for(let i=0;i<arr.length;i++){
        if(Array.isArray(arr[i])){
            arr=arr.flat();
            counter=0;
        }
        else{
            counter++;
        }
    }
    if(counter===arr.length){
        console.log(arr); // the arr here is nicely flattened
        return arr;
    }
    
    return flatArray(arr);
}

let arr2 = [22,4,[5],5,[2,[2,[2,5,8]]]];
let x = flatArray(arr2);
console.log(x); // here the value is undefined
3

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