Let arr = [0,1,2,3,4,5];
Let answer = arr.reduce((acc,curr) => {
If(curr == 2){
return "fresh";
}else{
return acc
}
})
console.log(answer)
If that else statement returning acc(which i didn’t set to anything) isn’t their it returns undefined…Why does it need that to work
Because every function in JavaScript by default returns undefined (nothing to do with reduce).
And if you don’t provide default value for acc in reduce, then for the first loop its value is the first element of the array and curr is the second.
I’ve edited your post for readability. When you enter a code block into a forum post, please precede it with a separate line of three backticks and follow it with a separate line of three backticks to make it easier to read.
You can also use the “preformatted text” tool in the editor (</>) to add backticks around text.
See this post to find the backtick on your keyboard.
Note: Backticks (`) are not single quotes (’).
I just simplified this…I used this for a much larger approach run the code…My question why isn’t it returning fresh…unless I return acc…
I was able to get it to return “fresh” when I uncapitalized the if and let keywords.
Those should be lowercase.
Did you remove the return acc in the else?
I just posted the screenshot.
Was that what you were looking for?
if (curr = 2) will always be true, so every iteration will return "fresh" and else will never be called 
But I guess it’s a typo just like Let and If.
This is crazy but I ran the exact thing you typed and got undefined
Okay nope your using…Assignment I used equality
What is your current code?
I just edited it sorry
Because acc value is the one you return from the callback function. And if you don’t have else it’ll be undefined.
Editing the first post makes it really hard to follow the conversation.
Anywho, it looks like you still have a typo where you have capitalized If
Am sorry don’t mind the capitalization
You can’t ignore the capitalization though. It has meaning
Okay now check (curr == 5) it returns fresh even without return acc
Because it’s the last item, no undefined to overwrite it.
let arr = [0,1,2,3,4,5];
let answer = arr.reduce((acc,curr) => {
if (curr == 2) {
return "fresh";
} else {
return acc;
}
})
console.log(answer);
is equivalent to
let arr = [0,1,2,3,4,5];
let acc = arr[0];
for (let i = 1; i < arr.len; i++) {
if (curr == 2) {
acc = "fresh";
} else {
acc = acc;
}
}
let answer = acc;
console.log(answer);
Thank You very much this is what has been confusing me all along…I never knew just returning “fresh” set acc to “fresh”