I keep doing this and it gives me the same result

JavaScript
1

Tell us what’s happening:
Describe your issue in detail here.

  **Your code so far**


function functionWithArgs(a,b){
console.log(1+2);
console.log(7+9)
}
functionWithArgs();

  **Your browser information:**

User Agent is: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/100.0.4896.127 Safari/537.36

Challenge: Passing Values to Functions with Arguments

Link to the challenge:

2

Thats because you are hard coding 1+2 and 7+9 in your function. You need to use the function parameters inside your function to use the values passed as arguments. So if you called functionWithArgs(4,3) the parameter a would hold 4, and b would hold 3. You can then add those together and get the correct result.

3

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