Passing Values to Functions with Arguments help

JavaScript
1

Tell us what’s happening:

Your code so far


// Example
function ourFunctionWithArgs(a, b) {
  console.log(a - b);
}
ourFunctionWithArgs(10, 5); // Outputs 5

// Only change code below this line.
function functionWithArgs(one, two) {
  console.log(one + two);
}

functionWithArgs(7 + 9);

Cant figure out whats wrong with this, looked up the hint but that didnt help much. looked to similar threads but couldnt find my solution
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Link to the challenge:
https://learn.freecodecamp.org/javascript-algorithms-and-data-structures/basic-javascript/passing-values-to-functions-with-arguments

2

Look at how the sample passes two arguments. How many arguments is your call to functionWithArgs() getting?

3

Notice the pattern:

ourFunctionWithArgs(a, b) {};
ourFunctionWithArgs(10, 5);

functionWithArgs(one, two) {};
functionWithArgs(7 + 9);

One of these things is not like the others, one of these things is not the same…

2 Likes
4

Drat!! Now i got that song stuck in my head!

1 Like
5

thanks bro. have a good one