**Tell us what’s happening:**

I have issues with evaluating the correct number of days that have passed. When the number of days passed become large, it seems to be one day behind what the actual value is for some reason (e.g. it says 19 days later instead of 20). The code works fine if its only 2 days later for example.

**Your code so far**

```
def get_days_later(days):
if days > 1:
return f" ({days} days later)"
elif days == 1:
return " (next day)"
else:
return ""
def add_time(time, add, day=None):
#Getting time data
time, period = time.split()
period = period.strip().upper()
hour, min = time.split(":")
add_hour, add_min = add.split(":")
# Variables
week = [
"monday",
"tuesday",
"wednesday",
"thursday",
"friday",
"saturday",
"sunday"
]
hour, min = int(hour), int(min)
add_hour, add_min = int(add_hour), int(add_min)
end_min = min + add_min
if end_min >= 60:
min = end_min % 60
hour += 1
else:
min = min + add_min
end_hour = hour + add_hour
cycles = end_hour // 12
days_passed = end_hour // 24
hour = end_hour % 12
# Calculating new time
if hour == 0:
hour = 12
if cycles % 2 != 0:
if period == "AM":
period = "PM"
elif period == "PM":
period = "AM"
# Formatting for printing
if min < 10:
min = f"0{min}"
if day:
days_index = week.index(day.lower())
final_day = week[(days_index + days_passed) % 7].title()
return f"{hour}:{min} {period}, {final_day}{get_days_later(days_passed)}"
else:
return f"{hour}:{min} {period}{get_days_later(days_passed)}"
```

**Challenge:** Scientific Computing with Python Projects - Time Calculator

**Link to the challenge:**